The length of potentiometer wire is 600 cm and a current of 40 mA is flowing in it. When a cell of emf 2V and internal resistance 10 Ω Ω is balanced on this potentiometer the balance length is found to be 500 cm. The resistance of potentiometer wire will be-
Text Solution
Verified by ExpertsThe correct answer is:
C
Potential difference of external circuit 
Potential gradient × Balance length.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The balancing length for a cell is 560 cm in a potentiometer experiment. When an external resistanc…
The series combination of two batteries, both of the same emf 10V, but different internal resistanc…
Four resistances of 15 Ω Ω , 12 Ω Ω , 4 Ω Ω and 10 Ω Ω respectively in cyclic order to form Wheatst…
Match the following:
The following table gives the lengths of four copper rods at the same temperat…
Match the statements in Column I with the current element in Column II
Column - IColumn - II(A)Curr…
A continuous beam of electrons emitted by a heating filament are accelerated in free space by an el…